Super Seth is a 3-year-old Colt, based at Mornington. With 8 career starts and 5 wins, it has earned $1,512,100.
| Date | Track | Dist | Class | Going | Bar | Wgt | Jockey | Result | Margin | Time | SP | Winner / 2nd |
|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 4 Apr 2020 | Randwick | 1600m | Open | H8 | 2 | 55kg | Robbie Dolan | 8th of 20 | 2.9L | 1:37.77 | $17 | 1-Nettoyer |
| 21 Mar 2020 | Rosehill | 1500m | Open | So5 | 9 | 56kg | Mark Zahra | 7th of 9 | 4.3L | 1:30.15 | $6.50 | 1-Dreamforce |
| 12 Mar 2020 | Randwick | 1045m | Btria | So6 | 2 | — | Mark Zahra | 2nd of 8 | 0.1L | 1:02.80 | 1-Kementari | |
| 22 Feb 2020 | Caulfield | 1400m | Open | G3 | 4 | 55.5kg | Mark Zahra | 2nd of 8 | 0.2L | 1:21.90 | $2.60F | 1-Streets Of Avalon |
| 1 Feb 2020 | Caulfield | 1200m | Open | So7 | 1 | 59.5kg | Mark Zahra | 1st of 6 | 1.3L | 1:12.83 | $5 | 2-Free Of Debt |
| 12 Oct 2019 | Caulfield | 1600m | Open | G3 | 4 | 56.5kg | Mark Zahra | 1st of 16 | 0.1L | 1:36.44 | $7.50 | 2-Alligator Blood |
| 29 Sept 2019 | Caulfield | 1400m | Open | G4 | 14 | 57kg | Mark Zahra | 5th of 15 | 6.2L | 1:23.49 | $14 | 1-Alligator Blood |
| 14 Sept 2019 | Flemington | 1200m | Open | G3 | 2 | 58.5kg | Mark Zahra | 6th of 10 | 2L | 1:09.40 | $4.80 | 1-Dalasan |
| 31 Aug 2019 | Caulfield | 1200m | Open | G3 | 6 | 57kg | Mark Zahra | 1st of 8 | 1.3L | 1:10.95 | $3.60F | 2-King Of Hastings |
| 25 Apr 2019 | Flemington | 1400m | Open | G4 | 4 | 59kg | Mr C Douglas | 3rd of 7 | 2.6L | 1:25.61 | $1.40F | 1-Chaillot |
| 13 Apr 2019 | Caulfield | 1200m | Open | G4 | 2 | 55.5kg | Mr C Douglas | 1st of 11 | 1L | 1:10.50 | $1.65F | 2-Stand To Attention |
| 24 Mar 2019 | Ballarat | 1200m | Mdn | G4 | 12 | 58kg | Mark Zahra | 1st of 12 | 6L | 1:12.04 | $1.75F | 2-Baileys |
| Condition | Starts | Record | Win % | Place % |
|---|---|---|---|---|
| This track | 5 | 4-0-0 | 80% | 80% |
| This distance | 2 | 0-0-1 | 0% | 50% |
| Good | 7 | 4-0-1 | 57% | 71% |
| Soft | 1 | 1-0-0 | 100% | 100% |
| First-up | 3 | 3-0-0 | 100% | 100% |
| Second-up | 2 | 1-0-0 | 50% | 50% |
1(1600), 4(1200)